Typeerror: method object is not subscriptable

Are you struggling to fix this “typeerror: method object is not subscriptable error message”?

Therefore, keep on reading, as we are going to show you how you can fix it with simple yet effective solutions.

Aside from that, in this article, you’ll have a better understanding of “method object is not subscriptable.”

What is “typeerror: method object is not subscriptable”?

The “typeerror: ‘method’ object is not subscriptable” is an error message in Python.

That is usually raised when you use square brackets [] to call a method instead of parenthesis or round brackets ().

In addition to that, this error message indicates that you are trying to use the square bracket [] syntax to access the method object, which is not allowed.

A method in Python, is a function that is associated with an object, and cannot be accessed directly with square brackets [].

How to fix “typeerror: method object is not subscriptable”?

To fix this error, you have to make sure that you are using the correct syntax.

By replacing the square brackets [] with round brackets () after the method’s name when you are calling it.

For instance, if you have a method called sample_list and you are calling it like this: sample_list. append [4], you should change it to sample_list.append(4).

Incorrect code:


sample_list = [1, 2, 3]
result = sample_list.append[4] # This line will produce the error

Correct code


sample_list = [1, 2, 3]
result = sample_list.append(4) # This line will not produce the error

Here are the following solutions you may use to resolve this ‘”method’ object is not subscriptable” type error:

1: Using parentheses to call the method

If you’re trying to access the method object using square brackets.

You can fix the error by simply calling the method with any required arguments instead.

sample_list = [1, 2, 3, 4, 5]
sample_method = sample_list.append
sample_method(6)
print(sample_list[2])

Output:

3

2: Use call() method

The alternative way to call a method object is to use its call() method.

my_list = [10, 20, 30, 40, 50]
my_method = my_list.append
my_method.__call__(6)
print(my_list[2])

Output:

30

3: Use methods get() and append_all()

Here’s the example code that shows how to access the methods get() and append_all() correctly using a custom list:

class SampleList:

    def __init__(self, lst):
        self.lst = lst

    def get(self, index):
        return self.lst[index]

    def append_all(self, lst):
        self.lst.extend(lst)


sample_list = SampleList(['Itsourcecode'])
sample_list.append_all(['sourcecodehero', 'ITSC'])
print(sample_list.get(1))

Output:

sourcecodehero

Conclusion

By using the provided solutions above, you can fix the “typeerror: method object is not subscriptable” error and access the method object correctly.

To avoid this error, simply do not call methods using the square bracket [].

We are hoping that this article provided you with sufficient solutions to get rid of the error.

You could also check out other “typeerror” articles that may help you in the future if you encounter them.

Thank you very much for reading to the end of this article.

Frequently Asked Questions

What is Python TypeError and what causes it?

TypeError is raised when an operation is applied to an object of the wrong type. Common patterns: calling a non-callable object, adding incompatible types (str + int), passing the wrong number of arguments, or accessing attributes on a NoneType. Each TypeError message names the operation and expected vs actual types, the fix is almost always to convert types explicitly (int(), str()) or fix the wrong variable assignment.

How do I quickly debug a Python TypeError?

Three steps: (1) Read the full error message, it names the exact operation and types involved. (2) Print the type of every variable in that line: print(type(var1), type(var2)). (3) Check what the function expected vs what you passed. Most TypeError fixes are 1-line type casts or fixing a variable that became None unexpectedly.

Should I catch TypeError or let it propagate?

For internal code, let TypeError propagate, it’s almost always a real bug (wrong type passed). For boundary code (parsing user input, third-party API responses), catch TypeError + ValueError together: try: parsed = int(value) except (TypeError, ValueError): parsed = 0. Catching internal TypeErrors hides bugs.

How do I prevent TypeError in production?

Three patterns: (1) Use type hints (def add(a: int, b: int) -> int) and check with mypy / pyright in CI. (2) Validate inputs at boundaries (Pydantic for FastAPI, DRF serializers for Django). (3) Default values that match expected types (return 0 not None for numeric functions). Static typing catches 80% of TypeErrors before runtime.

Where can I find more TypeError fixes?

Browse the TypeError reference hub for 220+ specific TypeError fixes. For broader Python debugging, see the Python Tutorial hub. For related error types, see ValueError and AttributeError guides.

Caren Bautista

Technical Writer at PIES IT Solution

Responsible for crafting clear, well-structured, and beginner-friendly content across the platform. Handles the writing, proofreading, and editorial review of tutorials, guides, and documentation to ensure every article is accurate, readable, and easy to follow.

Expertise: Technical Writing · Content Creation · Documentation · Editorial Writing · JavaScript · TypeScript · Python · Python Errors · HTTP Errors · MS Excel  · View all posts by Caren Bautista →